Many sites have explanation about op-amps, most of them gives you ready equations that fit only for a specific case.
I will explain you where these equations come from and how you can solve other circuits even if any resistor changed to a capacitor or diode or anything else.
Symbol:
VCC – positive rail of power supply (usually >0V)
VEE – Negative rail of power supply (usually <=0)
note: – sometimes VCC and VEE don’t appear on circuits, just noticed that op-amp connected to +/- 12V (for example)
Vout – out put voltage of op-amp (output voltage can be in range of VCC<Vout<VEE)
V- - negative input of op-amp
V+ - positive input of op-amp
VEE – Negative rail of power supply (usually <=0)
note: – sometimes VCC and VEE don’t appear on circuits, just noticed that op-amp connected to +/- 12V (for example)
Vout – out put voltage of op-amp (output voltage can be in range of VCC<Vout<VEE)
V- - negative input of op-amp
V+ - positive input of op-amp
Property of op-amp
- Input impedance, of positive input (V+) and negative input (V-), are very big. We can assume that it is infinite.
- Output impedance of op-amp is very low, we can assume it as 0Ohm.
Negative op-amp feedback (Inverting Amplifier)
At negative op-amp feedback, op-amp will do anything to make V+=V- - this sentence will solve you all problems.
Let assume that current flow according to red arrow.
According to property 1 that I mentioned above, I1 must be equal to I2 – no current is flow into op-amp inputs.
As I told before, op-amp will do everything it can to make V+=V- (when I say " will do everything it can" I mean that Vout will be changed this way to make V+=V-)
Now I guess you are asking yourself "How is it helping me to solve a circuit with a capacitor or a diode?", am I right?
It is the exactly the same solution way, all what is changeing is the connection between current and voltage. For example, let take a capacitor.
Now, for an example, I will assume that the current flow to an opposite direction.
As I mentioned above V+=V- on negative feedbacks, in this case V+=V-=0V
For constant Vin voltage wel will get the following equation:
The output voltage will look like this:
The slope of the graph is
If Vin is an alternative voltage then the output voltage can be calculated this way:
Now if you want to put a diode somewhere, all you need to do is to use diode current voltage equation that is:
non-inverting op-amp
The different between inverting amplifier and non-inverting amplifier is where you supply the input signal.
If you supply the signal to negative input (V-), like we did before it will be inverting amplifier and the output will be inverted to the input.
The graph below shows input voltage ( Vin - the bule line) and output voltage (Vout - the red line)
Do you remember that Vout= -Vin * R1/R2 for inverting op-amp?
So in this case Vin=2Vptp and Vout=-20Vptp so A=R1/R2=10.
A=Vout/Vin=-20/2=-10Now let see how we create an eqution for non inverting amplifier.
noninverting opamp looks this way:
As I already mentioned before, I1=I2 in vegative feedback:
Also V+=V- in this case V+=V-=Vin so
Now let figure Vout:
The graph below shows input voltage ( Vin - the bule line) and output voltage (Vout - the red line)
In this case R1/R2=9